(3x^3-4x^2+9)-(9-4x^2+3x^3)=

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Solution for (3x^3-4x^2+9)-(9-4x^2+3x^3)= equation:


Simplifying
(3x3 + -4x2 + 9) + -1(9 + -4x2 + 3x3) = 0

Reorder the terms:
(9 + -4x2 + 3x3) + -1(9 + -4x2 + 3x3) = 0

Remove parenthesis around (9 + -4x2 + 3x3)
9 + -4x2 + 3x3 + -1(9 + -4x2 + 3x3) = 0
9 + -4x2 + 3x3 + (9 * -1 + -4x2 * -1 + 3x3 * -1) = 0
9 + -4x2 + 3x3 + (-9 + 4x2 + -3x3) = 0

Reorder the terms:
9 + -9 + -4x2 + 4x2 + 3x3 + -3x3 = 0

Combine like terms: 9 + -9 = 0
0 + -4x2 + 4x2 + 3x3 + -3x3 = 0
-4x2 + 4x2 + 3x3 + -3x3 = 0

Combine like terms: -4x2 + 4x2 = 0
0 + 3x3 + -3x3 = 0
3x3 + -3x3 = 0

Combine like terms: 3x3 + -3x3 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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